Clarify the readme, add the echo example program, and prettyfy the ascii example program
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CrazyEttin
parent
394137950f
commit
38080674f5
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@ -3,14 +3,19 @@
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;Print a prompt
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load r0, prompt
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store ffff, r0
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load r0, space
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store ffff, r0
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;Read a character to r0 and load it to r2
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load r0, ffff
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xor r2, r2
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xor r2, r0
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;Print a newline
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;Print a newline and align
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cleq r0, r0, newln
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load r1, space
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store ffff, r1
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store ffff, r1
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;Get the hexadecimal digit of the high nibble
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ror r0
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@ -119,9 +124,10 @@ dgtf: load r0, tbl1f
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n2hend: ret
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;Characters
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prompt: data 3e
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cr: data d
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lf: data a
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space: data 20
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prompt: data 3e
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;Mask
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mask: data f
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@ -0,0 +1,197 @@
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;String echo
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;Store the buffer start address in buffst
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;High byte
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load r0, chstor + 1
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store buffst, r0
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;Low byte
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load r0, chstor + 2
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store buffst + 1, r0
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;Print a prompt
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start: load r0, prompt
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store ffff, r0
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load r0, space
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store ffff, r0
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;Initialise the character counter
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xor r0, r0
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;Read a character
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inloop: load r1, ffff
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;Check for an escape
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load r2, esc
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breq r1, r2, escbr
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;Check for a return
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load r2, cr
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breq r1, r2, inend
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;Check for end of the buffer
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load r2, buffsz
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brneq r0, r2, chstor
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;Backtrack if end of the buffer
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load r2, bs
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store ffff, r2
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breq r0, r0, inloop
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;Store the character in the buffer
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chstor: store buffer, r1
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;Increment the character counter and load it in r3
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load r2, one
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cleq r0, r0, sum
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xor r3, r3
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xor r3, r0
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;Increment the buffer address
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;High byte
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load r0, chstor + 1
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load r2, one
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cleq r0, r0, sum
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store chstor + 1, r0
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;Low byte
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load r0, chstor + 2
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load r2, one
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cleq r0, r0, sum
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store chstor + 2, r0
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;Add the overflow to the high byte
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load r0, chstor + 1
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xor r2, r2
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xor r2, r1
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cleq r0, r0, sum
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store chstor + 1, r0
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;Reload the character counter to r0
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xor r0, r0
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xor r0, r3
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;Read the next character
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breq r0, r0, inloop
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;Print a backslash and a newline
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escbr: load r0, space
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store ffff, r0
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load r0, bslash
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store ffff, r0
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load r0, cr
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store ffff, r0
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load r0, lf
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store ffff, r0
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;Restore the buffer address to its start
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;High byte
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load r0, buffst
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store chstor + 1, r0
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;Low byte
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load r0, buffst + 1
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store chstor + 2, r0
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;Start a new input line
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breq r0, r0, start
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;Store a string-terminating zero in the buffer
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inend: xor r0, r0
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load r1, chstor + 1
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store endsto + 1, r1
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load r1, chstor + 2
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store endsto + 2, r1
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endsto: store 0000, r0
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;Print a line feed and align with the input
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load r0, lf
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store ffff, r0
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load r0, space
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store ffff, r0
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store ffff, r0
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;Load a character from the buffer
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outlop: load r1, buffer
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;Check for string end
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xor r2, r2
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breq r1, r2, outend
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;Print the character
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store ffff, r1
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;Increment the buffer address
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;High byte
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load r0, outlop + 1
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load r2, one
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cleq r0, r0, sum
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store outlop + 1, r0
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;Low byte
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load r0, outlop + 2
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load r2, one
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cleq r0, r0, sum
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store outlop + 2, r0
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;Add the overflow to the high byte
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load r0, outlop + 1
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xor r2, r2
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xor r2, r1
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cleq r0, r0, sum
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store outlop + 1, r0
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;Print the next character
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breq r0, r0, outlop
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;Print a newline
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outend: load r0, cr
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store ffff, r0
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load r0, lf
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store ffff, r0
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;Halt
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halt
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;Add r2 to r0 with the overflow stored in r1
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;Reset overflow
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sum: xor r1, r1
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store ovrflw, r1
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;Copy the first argument to r1
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sumlop: xor r1, r1
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xor r1, r0
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;Calculate the sum and carry and copy the pre-shift carry to r1
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xor r0, r2
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and r2, r1
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xor r1, r1
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xor r1, r2
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shl r2
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;Check for overflow
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rol r1
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breq r1, r2, nvrflw
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;Store overflow
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load r1, one
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store ovrflw, r1
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;Check for no carry
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nvrflw: xor r1, r1
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breq r1, r2, sumend
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;Loop
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breq r0, r0, sumlop
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;Load overflow and return
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sumend: load r1, ovrflw
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ret
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;Constants
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one: data 1
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;Characters
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bs: data 8
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lf: data a
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cr: data d
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esc: data 1b
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space: data 20
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prompt: data 3e
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bslash: data 5c
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;Variables
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ovrflw: data 0
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;Buffer
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buffst: data 0
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data 0
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buffsz: data f
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buffer:
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@ -11,7 +11,7 @@ Registers and Memory
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* 24-bit instruction register IR
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* 16-bit instruction and return pointers IP and RP
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* 8-bit general-purpose registers R0-R3
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* 8-bit memory addresses 0-FFFF
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* 8-bit memory locations 0-FFFF
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Multi-byte values are big-endian. Memory addresses FFF0-FFFF are
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reserved for memory mapped devices; the instruction and return pointers
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